SOLUTION: Determine the values of sin2x, cos2x, and tan2x: Sinx=3/5, and x is acute

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Question 170929: Determine the values of sin2x, cos2x, and tan2x:
Sinx=3/5, and x is acute

Answer by Edwin McCravy(20059) About Me  (Show Source):
You can put this solution on YOUR website!
Determine the values of Sin%282x%29, Cos%282x%29, and Tan%282x%29:

Sin%28x%29=3%2F5, and x is acute

Since SINE=%28OPPOSITE%29%2F%28HYPOTENUSE%29

We can let the opposite side be the numerator of 3%2F5,
which is 3, and the hypotenuse be the denominator
of 3%2F5 which is 5, so we draw this picture:

 


Now we find the adjacent side by the Pythagorean theorem:

hypotenuse%5E2=opposite%5E2%2Badjacent%5E2
5%5E2=3%5E2%2Badjacent%5E2
25=9%2Badjcent%5E2
16=adjacent%5E2
sqrt%2816%29=sqrt%28adjacent%5E2%29
4=adjacent

So we label the adjacent side as 4



To find Sin%282x%29, we use this identity:

sin%282x%29=2sin%28x%29Cos%28x%29

We are given Sin%28x%29=3%2F5 but we do not have Cos%28x%29.

Since COSINE=%28ADJACENT%29%2F%28HYPOTENUSE%29

Cos%28x%29=4%2F5

sin%282x%29=2sin%28x%29Cos%28x%29
sin%282x%29=2%283%2F5%29%284%2F5%29
sin%282x%29=2%2812%2F25%29
sin%282x%29=24%2F25

To find Cos%282x%29, we use this identity:

Cos%282x%29=Cos%5E2x+-+Sin%5E2x
Cos%282x%29=%284%2F5%29%5E2-%283%2F5%29%5E2%0D%0A%7B%7B%7BCos%282x%29=16%2F25-9%2F25
Cos%282x%29=7%2F25.

To find +Tan%282x%29+, we can use this identity:

Tan%282x%29=%28+Sin%282x%29+%29%2F%28+Cos%28x%29+%29+
Tan%282x%29=%2824%2F25%29%2F%287%2F25%29
Tan%282x%29=%2824%2F25%29%2A%2825%2F7%29
Tan%282x%29=%2824%2Fcross%2825%29%29%2A%28cross%2825%29%2F7%29
Tan%282x%29=24%2F7

Edwin