SOLUTION: At 7:00 a.m., Joe starts jogging at 6 mph. At 7:10 a.m., Ken starts off after him. How fast must Ken run in order to overtake him at 7:30 a.m.?

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Question 170799: At 7:00 a.m., Joe starts jogging at 6 mph. At 7:10 a.m., Ken starts off after him. How fast must Ken run in order to overtake him at 7:30 a.m.?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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At 7:00 a.m., Joe starts jogging at 6 mph. At 7:10 a.m., Ken starts off after him. How fast must Ken run in order to overtake him at 7:30 a.m.?
:
From the information given we can say:
Joe's travel time = 1%2F2 hr
Ken's travel time = 1%2F3 hr
:
Let s = Ken's jogging speed
:
When Ken overtakes Joe, they will have traveled the same distance
Write a distance equation from this fact; Dist = Time * speed
:
Kens dist = Joe's dist
1%2F3s = 1%2F2*6
:
Multiply both sides by 6 to get rid of the denominators
2s = 3*6
2s = 18
s = 9 mph is Ken's speed
:
:
Check solution by finding the dist:
1%2F3* 9 = 3 mi
1%2F2* 6 = 3 mi