SOLUTION: Solve using the elimination method. 2x - y = 6 5x + y = 22

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Question 170660This question is from textbook Introductory Algebra
: Solve using the elimination method.
2x - y = 6
5x + y = 22
This question is from textbook Introductory Algebra

Found 2 solutions by jim_thompson5910, Mathtut:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

Start with the given system of equations:
system%282x-y=6%2C5x%2By=22%29


Add the equations together. You can do this by simply adding the two left sides and the two right sides separately like this:


%282x-1y%29%2B%285x%2By%29=%286%29%2B%2822%29


%282x%2B5x%29%2B%28-1y%2B1y%29=6%2B22 Group like terms.


7x%2B0y=28 Combine like terms. Notice how the y terms cancel out.


7x=28 Simplify.


x=%2828%29%2F%287%29 Divide both sides by 7 to isolate x.


x=4 Reduce.


------------------------------------------------------------------


2x-1y=6 Now go back to the first equation.


2%284%29-1y=6 Plug in x=4.


8-1y=6 Multiply.


-y=6-8 Subtract 8 from both sides.


-y=-2 Combine like terms on the right side.


y=%28-2%29%2F%28-1%29 Divide both sides by -1 to isolate y.


y=2 Reduce.


So our answer is x=4 and y=2.


Which form the ordered pair .


This means that the system is consistent and independent.


Notice when we graph the equations, we see that they intersect at . So this visually verifies our answer.


Graph of 2x-y=6 (red) and 5x%2By=22 (green)

Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
2x-y=6....eq 1
5x+y=22...eq 2
:
this problem is already set up nicely without having to multiply either equation by anything. Just add eq1 to eq 2 and the y terms will be eliminated.
:
we are left with
the x terms 2x+5x and the constants 6+22
:
2x+5x=6+22
:
7x=28
:
highlight%28x=4%29
now substitute x's value back into either equation....I will use eq 2
:
5(4)+y=22---->20+y=22--->subtraction 20 frome each side produces
highlight%28y=2%29