SOLUTION: Find the dimensions of a rectangle whose perimeter is 46m and whose area is 126m^2.

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Question 170632This question is from textbook Algebra structure and method book one
: Find the dimensions of a rectangle whose perimeter is 46m and whose area is 126m^2. This question is from textbook Algebra structure and method book one

Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
P=2L+2W
A=L*W
46=2L+2W
126=L*W OR L=126/W
46=2(126/W)+2W
46=252/W+2W
46=(252+2W*W)/W
46=(252+2W^2)/W
46W=252+2W^2
2W^2-46W+252=0
2(W^2-23W+126)=0
2(W-14)(W-9)=0
W-14=0
W=14 & L=9
W-9=0
W=9 & L=14
PROOF:
46=2*14+2*9
46=28+18
46=46
14*9=126
126=126