Question 170334: HELP! I am completely stuck on this problem:
A twin-engined air craft can fly 1200 miles from city A to city B in 5 hours with the wind and make the return trip in 8 hours against the wind. what is the speed of the wind?
I have solved so many of these before in geometry, but that was over a year ago, and I can't remember how to solve it.
When I attempted to figure it out, I was not sure if the equation with the wind was 5+X and if the one against the wind was 8-X, or x-8.
Thanks so much for the help! it really means a lot!
Answer by checkley77(12844)   (Show Source):
You can put this solution on YOUR website! 1200/5=240 MPH WITH THE WIND.
1200/8=150 MPH FOR THE RETURN TRIP AGAINST THE WIND.
(240-150)/2=90/2=45 MPH IS THE SPEED OF THE WIND.
PROOF:
240-45=195
150+45=195 THE SPEED OF THE PLANE
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