SOLUTION: We have to solve using the eliminaiton or substitution method. I am really struggling with this class so I'm not sure where to start.
2(x-y)=3+x which is 2x - 2y =3+x
x = 3y
Algebra ->
Expressions-with-variables
-> SOLUTION: We have to solve using the eliminaiton or substitution method. I am really struggling with this class so I'm not sure where to start.
2(x-y)=3+x which is 2x - 2y =3+x
x = 3y
Log On
Question 170288This question is from textbook
: We have to solve using the eliminaiton or substitution method. I am really struggling with this class so I'm not sure where to start.
2(x-y)=3+x which is 2x - 2y =3+x
x = 3y + 4 This question is from textbook
You can put this solution on YOUR website! First order of business, put all the x's and y's to one side:
2x - 2y =3+x
x = 3y + 4
.
Rearranging then, we have:
x - 2y =3
x - 3y =4
.
Now, using the "elimination method", subtract the second equation from the first:
x - 2y = 3
-x + 3y = -4
---------------
y = -1
.
Now, use the above definition of 'y' and substitute it into equation 2:
x = 3y + 4
x = 3(-1) + 4
x = -3 + 4
x = 1
.
Solution:
(x,y) = (1, -1)
You can put this solution on YOUR website! Solve the system:
1) and
2)
The idea behind the "elimination" or "substitution" method is to reduce the problem from two equations with two unknowns (variables) to one equation with one unknown. This is accomplished by "eliminating" one of the unknowns.
In this problem, you can conveniently substitute the x in the first equation with the x in the second equation, thus eliminating the x-variable.
It would be simpler to first simplify the first equation as you have started to do.
1) Subtract x from both sides. Now substitute the x from equation 2) Simplfy and solve for y. Combine like-terms. Subtract 4 from both sides. Now substitute this value of y into equation 2) and solve for x. Substitute y = -1 So the solution is: (1, -1) and the solution shows the point of intersection of the two lines represented by the two linear equations.
(