SOLUTION: 4x+3z=4 2y-6z=-1 8x+4y+3z=9 first i added equations 1 &2, But since the equations don't have the same variables i substituted the missing variables with zero.

Algebra ->  College  -> Linear Algebra -> SOLUTION: 4x+3z=4 2y-6z=-1 8x+4y+3z=9 first i added equations 1 &2, But since the equations don't have the same variables i substituted the missing variables with zero.       Log On


   



Question 170216This question is from textbook beginning and intermediate algebra
: 4x+3z=4
2y-6z=-1
8x+4y+3z=9


first i added equations 1 &2, But since the equations don't have the same variables i substituted the missing variables with zero.
4x+0y+3z=4
0x+2y-6z=-1 my answer was 8x+2y=7 i canceled the z's. i still could not get the anwer right. Please help.
This question is from textbook beginning and intermediate algebra

Answer by Edwin McCravy(20066) About Me  (Show Source):
You can put this solution on YOUR website!
system%284x%2B3z=4%2C2y-6z=-1%2C8x%2B4y%2B3z=9%29

Remember, the idea is to have the SAME variable
missing in two equations, not just to eliminate
any variable you can.

You should start either of the following two 
ways, but not the way you started.  

1. Take advantage of the fact that y is already 
missing in the 1st equation. To do so, use the other 
two equations, 2nd and 3rd, to get another 
equation with y missing.  Then solve that with
the 1st.

or

2. Take advantage of the fact that x is already 
missing in the 2nd equation. To do so, use the other 
two equations, 1st and 3rd, to get another 
equation with x missing.  Then solve that with
the 2nd.

I'll arbitrarily choose the first way.

Since y is already eliminated in the first equation,
4x%2B3z=4
let's put it aside for now, and use only the other two
equations to eliminate y, the same variable that is
missing in the first.

system%282y-6z=-1%2C8x%2B4y%2B3z=9%29

We'll write 2y-6z=-1 as 0x%2B2y-6z=-1

system%280x%2B2y-6z=-1%2C8x%2B4y%2B3z=9%29

Remember we want to eliminate y, so we multiply
the upper equation through by -2 and add
it to the lower equation:

system%280x-4y%2B12z=2%2C8x%2B4y%2B3z=9%29

We add term by term and get

8x%2B15z=11

Now we go back and get the very first original
equation which we put aside, 4x%2B3z=4

We put it together with the one we just found
and now we have a system of two equations with 
the SAME missing variable, y. 

system%284x%2B3z=4%2C8x%2B15z=11%29 

Now we eliminate x by multiplying the
upper equation through by -2, and adding:

system%28-8x-6z=-8%2C8x%2B15z=11%29

and get

9z=3
z=3%2F9
z=1%2F3

Substitute this into 4x%2B3z=4

4x%2B3z=4
4x%2B3%281%2F3%29=4
4x%2B1=4
4x=3
x=3%2F4

Now substitute these values in either one of the 
original equations which contains y. The 
simpler one is 2y-6z=-1

2y-6z=-1
2y-6%281%2F3%29=-1
2y-2=-1
2y=1
y=1%2F2

So the solution is x=3%2F4, y=1%2F2, z=1%2F3

Edwin