SOLUTION: 90) 3^2x -8 . 3^x +15=0 94) If x= (log125 5)^log5 125 Please help me to solve this two. Thank You
Algebra
->
Logarithm Solvers, Trainers and Word Problems
-> SOLUTION: 90) 3^2x -8 . 3^x +15=0 94) If x= (log125 5)^log5 125 Please help me to solve this two. Thank You
Log On
Algebra: Logarithm
Section
Solvers
Solvers
Lessons
Lessons
Answers archive
Answers
Click here to see ALL problems on logarithm
Question 170138
This question is from textbook
intermediate algebra
:
90) 3^2x -8 . 3^x +15=0
94) If x= (log125 5)^log5 125
Please help me to solve this two. Thank You
This question is from textbook
intermediate algebra
Answer by
jim_thompson5910(35256)
(
Show Source
):
You can
put this solution on YOUR website!
Table of Contents:
Problem #90
Problem #94
Jump to Top
90)
Start with the given equation
Let
. So this means that
(ie
)
Replace
with
and
with "z" (see above)
Notice we have a quadratic equation in the form of
where
,
, and
Let's use the quadratic formula to solve for z
Start with the quadratic formula
Plug in
,
, and
Negate
to get
.
Square
to get
.
Multiply
to get
Subtract
from
to get
Multiply
and
to get
.
Take the square root of
to get
.
or
Break up the expression.
or
Combine like terms.
or
Simplify.
Now remember, we let
. So this means that
or
Start with the first equation
Take the log base 3 of both sides (to isolate "x")
------------------------------------------------
Move onto the second equation
Take the log base 3 of both sides (to isolate "x")
Evaluate the log base 3 of 3 to get 1
============================================================
Answer:
So the solutions are
or
Jump to Top
94)
Is the equation
????
If so, then....
Start with the given equation
Let
and
So the equation then becomes...
Now let's evaluate the individual pieces:
Start with the first assignment
Use the change of base formula to break up the log
Rewrite 125 as
. Note:
Pull the exponent down and place it out front.
Divide and cancel out the common terms.
Since
, this means that
(this is the first piece)
-------------------------------------------------------
Now move onto the second assignment
Use the change of base formula to break up the log
Rewrite 125 as
. Note:
Pull down the exponent.
Divide and cancel out the common terms.
Since
, this means that
(which is the second piece)
Go back to the original equation
Plug in
and
Distribute the exponent.
Cube 1 to get 1. Cube 3 to get 27.
=========================================================
Answer:
So the answer is
This means that