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Question 170131: my problem reads, write the standard equation of each vertex, and these are the problems they give me
1. y^2-8y-8x+64=0
2. 36x^2-288x+25y^2-150y=99
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! write the standard equation of each vertex, and these are the problems they give me
1. y^2-8y-8x+64=0
Complete the square on the y-terms:
y^2-8y+16 =8x-64+16
(y-4)^2 = 8x-48
(y-4)^2 = 8(x-6)
The vertex is (6,4)
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2. 36x^2-288x+25y^2-150y=99
Complete the square on the x and on the y-terms:
36x^2-288x+? + 25y^2-150y+? = -99+?
36(x^2- 8x + 16) + 25(y^2 - 6y + 9) = -99 + 36*16 + 25*9
36(x-4)^2 + 25(y-3)^2 = 702
Divide thru by 702 to get:
(x-4)^2/19.5 + (y-3)^2/28.08 = 1
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center at (4,3)
vertices at (4,3+sqrt(28.08)) and (4(3-sqrt(28.08))
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Cheers,
Stan H.
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