SOLUTION: Could you help me solve this problem? if y varies inversely as x^2, and y=2 when x=4, what is the constant of the variation? 2? Thank you.

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Question 170005: Could you help me solve this problem?
if y varies inversely as x^2, and y=2 when x=4, what is the constant of the variation? 2?

Thank you.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
If y varies inversely as x^2," equation for this is:
yk%2Fx%5E2; inversely means, when x increases, y decrease
:
y=2 when x=4, what is the constant of the variation?
:
Substituting for y and x we have:
2 = k%2F4%5E2
2 = k%2F16
Multiply both sides by 16
2*16 = k
:
k = 32; (the constant of variation)
:
:
Check this: using k=32 and x=4
y = 32%2Fx%5E2
y = 32%2F16
y = 2