Question 169946: The sum of even integers between 1 and 48
Answer by chiefman(11)   (Show Source):
You can put this solution on YOUR website! taking the formula n+1,n+3,n+5....where n=1,2,3,4,........to get even integers we have
2,4,6,8,.......48 this becomes an arithmetic series ie
2+4+6+8+......+48 where first term(a)=2,common diffrence(d)=2
we first find the number of terms in this seies
using the formula  where L is the last term.
48=2+(n-1)2
n=24 therefore there are 24 terms.
Now we find the the sum using the formula
 where S=sum n=number of terms
S=[24/2(2*2+(24-1)2]
=12(4+46)
=600
therefore the sum is 600
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