SOLUTION: Could someone maybe tell me what I did wrong by these two problems;
(3a^2b)(-2ab^3)= 6a^3b4 (why is my answer wrong?)
or why is my answer wrong here; ab^2= 3(4)^2 = 3(4*4)=48
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-> SOLUTION: Could someone maybe tell me what I did wrong by these two problems;
(3a^2b)(-2ab^3)= 6a^3b4 (why is my answer wrong?)
or why is my answer wrong here; ab^2= 3(4)^2 = 3(4*4)=48
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Question 169912: Could someone maybe tell me what I did wrong by these two problems;
(3a^2b)(-2ab^3)= 6a^3b4 (why is my answer wrong?)
or why is my answer wrong here; ab^2= 3(4)^2 = 3(4*4)=48
It would be more than great if someone could help me out here =) Found 2 solutions by stanbon, Alan3354:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! what I did wrong by these two problems;
(3a^2b)(-2ab^3)= 6a^3b4 (why is my answer wrong?)
or why is my answer wrong here; ab^2= 3(4)^2 = 3(4*4)=48
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(3a^2b)(-2ab^3)= -6a^3b^4
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It looks like you have substituted 3 for a and 4 for b.
If that is correct your answer is correct.
ab^2 = 3(4^2) = 3*16 = 48
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Chers,
Stan H.
You can put this solution on YOUR website! Could someone maybe tell me what I did wrong by these two problems;
(3a^2b)(-2ab^3)= 6a^3b4 (why is my answer wrong?)
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You lost the minus sign. It's -6a^3b^4
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or why is my answer wrong here; ab^2= 3(4)^2 = 3(4*4)=48
It would be more than great if someone could help me out here =)
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I don't see a problem there.
(