SOLUTION: Please help me with this problem:
An object launched upward with an initial velocity of 14.7 m/s from a height of 49 m will have a height of s(t)= -4.9t^2+49, where s is in mete
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An object launched upward with an initial velocity of 14.7 m/s from a height of 49 m will have a height of s(t)= -4.9t^2+49, where s is in mete
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Question 169835: Please help me with this problem:
An object launched upward with an initial velocity of 14.7 m/s from a height of 49 m will have a height of s(t)= -4.9t^2+49, where s is in meters and t is in seconds. How long will it take the object to hit the ground?
Thank you. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! An object launched upward with an initial velocity of 14.7 m/s from a height of 49 m will have a height of s(t)= -4.9t^2+49, where s is in meters and t is in seconds. How long will it take the object to hit the ground?
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s(t) must be zero when the object hits the ground.
-4.9t^2+49 = 0
4.9t^2 = 49
t^2 = 49/4.9
Positive answer:
t = sqrt(49/4.9)
t = 3.1622... seconds
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Cheers,
Stan H.
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