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Question 169654: Photobucket
my question is :

a student graphed a system of inequalities, shading only the region containong the solutions of the sytem. Write a system of inequalities corresponding to the students graph. Explain how you arrived at your answer.

there is no isbn because this is a module book question

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
There are two lines graphed, so we need to find the equations of those two lines first. From there, we can find the inequalities.


Line 1: Line going through points (0,4) and (4,0)


So let's find the equation of line 1


First let's find the slope of the line through the points and


m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29 Start with the slope formula.


m=%280-4%29%2F%284-0%29 Plug in y%5B2%5D=0, y%5B1%5D=4, x%5B2%5D=4, and x%5B1%5D=0


m=%28-4%29%2F%284-0%29 Subtract 4 from 0 to get -4


m=%28-4%29%2F%284%29 Subtract 0 from 4 to get 4


m=-1 Reduce


So the slope of the line that goes through the points and is m=-1


Now let's use the point slope formula:


y-y%5B1%5D=m%28x-x%5B1%5D%29 Start with the point slope formula


y-4=-1%28x-0%29 Plug in m=-1, x%5B1%5D=0, and y%5B1%5D=4


y-4=-1x%2B-1%28-0%29 Distribute


y-4=-1x%2B0 Multiply


y=-1x%2B0%2B4 Add 4 to both sides.


y=-1x%2B4 Combine like terms.


y=-x%2B4 Simplify


So the equation that goes through the points and is y=-x%2B4



-------------------------------------------------------


Line 2: Line through the points (0,0) and (3,6)


So let's find the equation of line 2



First let's find the slope of the line through the points and


m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29 Start with the slope formula.


m=%286-0%29%2F%283-0%29 Plug in y%5B2%5D=6, y%5B1%5D=0, x%5B2%5D=3, and x%5B1%5D=0


m=%286%29%2F%283-0%29 Subtract 0 from 6 to get 6


m=%286%29%2F%283%29 Subtract 0 from 3 to get 3


m=2 Reduce


So the slope of the line that goes through the points and is m=2


Now let's use the point slope formula:


y-y%5B1%5D=m%28x-x%5B1%5D%29 Start with the point slope formula


y-0=2%28x-0%29 Plug in m=2, x%5B1%5D=0, and y%5B1%5D=0


y-0=2x%2B2%28-0%29 Distribute


y-0=2x%2B0 Multiply


y=2x%2B0%2B0 Add 0 to both sides.


y=2x%2B0 Combine like terms.


y=2x Remove the trailing zero


y=2x Simplify


So the equation that goes through the points and is y=2x



===================================================


So the system of equations(we'll convert them into inequalities later) is:

system%28y=-x%2B4%2Cy=2x%29



Now, notice how the shaded region is BELOW both of the lines. In other words, EVERY point in the shaded region has a y-coordinate that is less than a point on either line.


So this means that we can take y=-x%2B4 and convert it to y%3C-x%2B4 (since every point in this shaded region is below the line y=-x%2B4) and we can take y=2x and convert it to y%3C2x (since every point in this shaded region is below the line y=2x)


So we then end up with the system of inequalities

system%28y%3C-x%2B4%2Cy%3C2x%29


Note: If you are INCLUDING the boundaries, then you need to change the inequality signs from to like this:


system%28y%3C=-x%2B4%2Cy%3C=2x%29