Question 169645: what is an equation for the line perpendicular to the equation x+2y=8 going through the point (4,0) Found 2 solutions by Alan3354, jojo14344:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! what is an equation for the line perpendicular to the equation x+2y=8 going through the point (4,0)
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Find the slope, m, of the line by putting it in the slope-intercept form, y = mx+b.
x+2y=8
2y = -x+8
y = (-1/2)x + 4 so the slope is -1/2
Then, y-y1 = m*(x-x1) where (x1,y1) is the point (4,0)
y-0 = (-1/2)*(x-4)
y = (-1/2)x + 2 slope-int form
x + 2y = 4 standard form
You can put this solution on YOUR website! what is an equation for the line perpendicular to the equation x+2y=8 going through the point (4,0)
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We'll see 1st line :
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Now the line perpendicular has a
Thru points (4,0) via Slope Intercept form: , y-intercept
So the line eqn is: , Answer (Green Line)
As we see below,
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Thank you,
Jojo
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