SOLUTION: a right traingle has one vertex on thr graph y=x^2 at (x,y), ANOTHER AT THE origin, and the third on the (positive) y-axis at (0,y). Express the area A of the triangle as a functio

Algebra ->  Test -> SOLUTION: a right traingle has one vertex on thr graph y=x^2 at (x,y), ANOTHER AT THE origin, and the third on the (positive) y-axis at (0,y). Express the area A of the triangle as a functio      Log On


   

Question 169278: a right traingle has one vertex on thr graph y=x^2 at (x,y), ANOTHER AT THE origin, and the third on the (positive) y-axis at (0,y). Express the area A of the triangle as a function of x.
Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
since y=x%5E2
A=1/2 b h--------> b=y and h is sqrt%28x%5E2%29=x
so A=1/2 (y)(x)
:
as a function of x
:
A=%281%2F2%29%28x%5E2%29%28x%29
A=%281%2F2%29%28x%5E3%29