SOLUTION: Julie and Eric row their boat (at a constant speed) 45 miles downstream for 5 hours, helped by the current. Rowing at the same rate, the trip back against the current takes 9 hours

Algebra ->  Human-and-algebraic-language -> SOLUTION: Julie and Eric row their boat (at a constant speed) 45 miles downstream for 5 hours, helped by the current. Rowing at the same rate, the trip back against the current takes 9 hours      Log On


   



Question 169265: Julie and Eric row their boat (at a constant speed) 45 miles downstream for 5 hours, helped by the current. Rowing at the same rate, the trip back against the current takes 9 hours. Find the rate of the current.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let the current be s
Let the rate of the boat with no current be r
With the current:
d+=+%28r+%2B+s%29%2At
Against the current:
d+=+%28r+-+s%29%2At
-------------------
Given:
45+=+%28r+%2B+s%29%2A5
45+=+%28r+-+s%29%2A9
Rewriting these,
5r+%2B+5s+=+45
9r+-+9s+=+45
Multiply the 1st by 9 and the 2nd by 5
45r+%2B+45s+=+45%2A9
45r+-+45s+=+45%2A5
Add these equations
90r+=+45%2A14
Divide both sides by 45
2r+=+14
r+=+7
Substitute this back into a given equation
45+=+%287+%2B+s%29%2A5
9+=+7+%2B+s
s+=+2
The rate of the current is 2 mi/hr
check:
45+=+%28r+%2B+s%29%2A5
45+=+%287+%2B+2%29%2A5
45+=+45
------------
45+=+%28r+-+s%29%2A9
45+=+%287+-+2%29%2A9
45+=+45
OK