Question 169206: (x+5) acres facing the Seventy-five acres of land were purchased for $142 500. The land facing the highway cost $2700 per acre. The land facing the railroad cost $2200 per acre and the remainder cost $1450 per acre. There were 5 acres more facing the railroad than the highway. How much land was at each price?
Answer by checkley77(12844)   (Show Source):
You can put this solution on YOUR website! (x+5) acres facing the railroad @ 2,200
x acres facing the highway @ 2,700
75-(x+5)-x acres in the middle @1,450
142,500=2,200(x+5)+2,700x+1,450[75-(x+5)-x]
142,500=2,200x+11,000+2,700x+1,450[70-2x]
142,500=11,000+4,900x+101,500-2,900x
142,500-11,000-101,500=2,000x
30,000=2,000x
30,000/2,000=x
x=15 acres facing the highway.
15+5=20 acres facing the railroad.
75-15-20=40 acres in the middle.
Proof:
142,500=2,200*20+2,700*15+1,450*40
142,500=44,000+40,500+58,000
142,500=142,500
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