SOLUTION: Forty eight more than the second of three consecutive odd integers is the sum of the first and 2/3 of the third. Find the three integers.

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Question 169112: Forty eight more than the second of three consecutive odd integers is the sum of the first and 2/3 of the third. Find the three integers.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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Forty eight more than the second of three consecutive odd integers is the sum of the first and 2/3 of the third. Find the three integers.
:
The three integers: x, (x+2), (x+4)
:
(x+2) + 48 = x + 2%2F3(x+4)
:
Multiply equation by 3 to get rid of the fraction
3(x+2) + 3(48) = 3x + 2(x+4)
:
3x + 6 + 144 = 3x + 2x + 8
:
150 - 8 = 3x - 3x + 2x
:
142 = 2x
:
x = 71, the 1st odd integer
:
:
Check solution in the original equation
73 + 48 = 71 + 2%2F375
121 = 71 + 50