SOLUTION: Find four consecutive integers such that the sum of the first three exceeds twice the greatest integer by 4.

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Question 169110: Find four consecutive integers such that the sum of the first three exceeds twice the greatest integer by 4.
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
I see several of these "consecutive integer problems". We'll do this one, and then you can use a similar process to do the other two.
You are told there are foiur consecutive numbers. So let's call the smallest one "x". Then the other three numbers are (x+1), (x+2) and (x+3).
You are then told how those number 'relate' to each other. In this problem, that relationship is "the sum of the first three exceeds twice the greatest integer by 4." (The other problems you listed have a different relationship. Just use the one the problem gives you and then solve
SumOfTheFirstThree+=+%282%2AFourth%29+%2B+4
%28x+%2B+%28x%2B1%29+%2B+%28x%2B2%29%29+=+%282+%2A%28x%2B3%29%29+%2B+4+
+3x+%2B+3+=+2x%2B6+%2B+4
+3x+%2B+3+=+2x+%2B+10
x+=+7
So the numbers are 7, 8, 9, 10. Does 7+8+9 = (2*10) + 4???