SOLUTION: A beaker contains 400L of a solution that is 32% acid. How much water should be added to make a solution that is 25% acid? I need help in organizing a chart showing how I got my a
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-> SOLUTION: A beaker contains 400L of a solution that is 32% acid. How much water should be added to make a solution that is 25% acid? I need help in organizing a chart showing how I got my a
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Question 169040: A beaker contains 400L of a solution that is 32% acid. How much water should be added to make a solution that is 25% acid? I need help in organizing a chart showing how I got my answer. Thank you. Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! .32*400=.25(400+x)
128=100+.25x
.25x=128-100
.25x=28
x=28/.25
x=112 L of water is used.
128=.25(400+112)
128=.25*512
128=128
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