SOLUTION: What is the procedure for factoring -3t^3 +23^2+8t completely?

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Question 168982: What is the procedure for factoring -3t^3 +23^2+8t completely?
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
factoring -t __ -t(3t^2-23t-8)

looking for factors of -8 that can "combine" with 3 to get -23

factoring __ -t(3t+1)(t-8)