SOLUTION: Write the coefficient of the middle term as the sum of two numbers, whose product equals the last term. z^2-13z+30

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Question 168974: Write the coefficient of the middle term as the sum of two numbers, whose product equals the last term.
z^2-13z+30

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

Looking at the expression z%5E2-13z%2B30, we can see that the first coefficient is 1, the second coefficient is -13, and the last term is 30.


Now the question is: what two whole numbers multiply to 30 (the last term) and add to the second coefficient -13?


To find these two numbers, we need to list all of the factors of 30.


Factors of 30:
1,2,3,5,6,10,15,30
-1,-2,-3,-5,-6,-10,-15,-30


Note: list the negative of each factor. This will allow us to find all possible combinations.


These factors pair up and multiply to 30.
1*30
2*15
3*10
5*6
(-1)*(-30)
(-2)*(-15)
(-3)*(-10)
(-5)*(-6)

Now let's add up each pair of factors to see if one pair adds to the middle coefficient -13:


First NumberSecond NumberSum
1301+30=31
2152+15=17
3103+10=13
565+6=11
-1-30-1+(-30)=-31
-2-15-2+(-15)=-17
-3-10-3+(-10)=-13
-5-6-5+(-6)=-11



From the table, we can see that the two numbers -3 and -10 add to -13 (the middle coefficient).


So the two numbers -3 and -10 both multiply to 30 and add to -13


Now replace the middle term -13z with -3z-10z. Remember, -3 and -10 add to -13. So this shows us that -3z-10z=-13z.


z%5E2%2Bhighlight%28-3z-10z%29%2B30 Replace the second term -13z with -3z-10z.


So the expression breaks down into z%5E2-3z-10z%2B30