SOLUTION: Find three consecutive numbers such that twice the smallest number is 23 more than the largest.

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Question 168958: Find three consecutive numbers such that twice the smallest number is 23 more than the largest.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Find three consecutive numbers such that twice the smallest number is 23 more than the largest.
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1st: x
2nd: x+1
3rd: x+2
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EQUATION:
2x = x+2 + 23
x = 25
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x+1 = 26
x+2 = 27
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Cheers,
Stan H.