SOLUTION: Can you please help? . Please solve {{{ 64 = 4^(2x) 16^(3x^2) }}}, it is 16 to the exponent of (3x^2) . Thanks ahead of time, Levi

Algebra ->  Exponents -> SOLUTION: Can you please help? . Please solve {{{ 64 = 4^(2x) 16^(3x^2) }}}, it is 16 to the exponent of (3x^2) . Thanks ahead of time, Levi      Log On


   

Question 168865: Can you please help?
.
Please solve +64+=+4%5E%282x%29+16%5E%283x%5E2%29+, it is 16 to the exponent of (3x^2)
.
Thanks ahead of time, Levi
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Please solve +64+=+4%5E%282x%29+16%5E%283x%5E2%29+, it is 16 to the exponent of (3x^2)
----------------
+64+=+4%5E%282x%29+16%5E%283x%5E2%29+
+2%5E6+=+2%5E%284x%29+%2A+2%5E%2812x%5E2%29
+2%5E6+=+2%5E%284x+%2B+12x%5E2%29
12x%5E2+%2B+4x+=+6
6x%5E2+%2B+2x+-+3+=+0
x = -1/6 + sqrt(19)/6
x = -1/6 - sqrt(19)/6