Question 168783: How many gallons of 30% alcohol must be mixed with 60 gallons of 14% alcohol to obtain a solution that is 20% alcohol? Answer by Mathtut(3670) (Show Source):
You can put this solution on YOUR website! let A= # of gallons of 30% solution of alcohol
.3A+60(.14)=.2(60+A)
.3A+8.4=12+.2A----->subtract .2A and 8.4 from each side
:
.1A=3.6
: gallons of 30% solution of alcohol