Question 168672: solve:
1.(2a-7)(a+9)=0
2.64x^2-9=0
3.x(x+3)=18
factor:
1.2ab+2ay+bx+xy Found 2 solutions by checkley77, KnightOwlTutor:Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! 1.(2a-7)(a+9)=0
2A^2-7A+18A-63=0
2A^2+11A-63=0
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2.64x^2-9=0
(8X+3)(8X-3)=0
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3.x(x+3)=18
X^2+9X-18=0
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factor:
1.2ab+2ay+bx+xy
2A(B+Y)+X(B+Y)
(2A+X)(B+Y)
You can put this solution on YOUR website! 1.(2a-7)(a+9)=0
The solution to this quadratic equation is a=7/2 or a=-9
You need to set each factor to equal 0.
2.64x^2-9=0
Add 9 to both sides
Divide both sides by 64
x^2=9/64
Take the sq rt of the numerator and denominator
x=3/8
3.x(x+3)=18
Use the distributive property
x^2+3x=18
Subtract 18 from both sides
x^2+3x-18=0
This equation can be easily factored into
(x+6)(x-3)=0
The solutions for this quadratic equation are x=-6 and x=3
1.2ab+2ay+bx+xy
2a(b+y)+x(b+y)
since both terms contain b+y
you can then redistribute the terms (a+x)(b+y)
To double check use the FOIL method and see that you have the same equation you started with.
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