SOLUTION: Hi, I have a question on this problem (excuse me if i can't put the whole problem in parethese). here it is:
(2x^2 all over 3 times 5 all over x) divided by 6x^2 all over 25
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-> SOLUTION: Hi, I have a question on this problem (excuse me if i can't put the whole problem in parethese). here it is:
(2x^2 all over 3 times 5 all over x) divided by 6x^2 all over 25
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Question 168627: Hi, I have a question on this problem (excuse me if i can't put the whole problem in parethese). here it is:
(2x^2 all over 3 times 5 all over x) divided by 6x^2 all over 25
Could you please show me how to do this one? I'm really stuck on this one. Sorry I couldn't put it how I wanted. I hope you can understand. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! (2x^2 all over 3 times 5 all over x)
= [(2x^2)/3] * [5/x]
Multiply the numerators and multiply the denominators.
= [10x^2/3x]
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Cheers,
Stan H.
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