SOLUTION: 1. The length of a rectangle is three times the width. The area is 108in^2. Find the length and the width. is six. The sum of the squares of the two numbers is twenty-six. Find

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: 1. The length of a rectangle is three times the width. The area is 108in^2. Find the length and the width. is six. The sum of the squares of the two numbers is twenty-six. Find       Log On


   

Question 168592: 1. The length of a rectangle is three times the width. The area is 108in^2. Find the length and the width.
is six. The sum of the squares of the two numbers is twenty-six. Find the two numbers.2. The sum of two numbers
Answer by iluvbuilding429(41) About Me  (Show Source):
You can put this solution on YOUR website!
1. The length of a rectangle is three times the width. The area is 108in^2. Find the length and the width.
The formula for area of a rectangle is:
A=L%2Aw
Plug in the values you already know:
108=3w%2Aw
Start by dividing both sides by 3:
36=w%5E2
Now find the square root of both sides:
6=w
To find the length, multiply the width by 3.
L=6%2A3
Multiply:
L=18
So, your width is 6, and your length is 18.

2. The sum of two numbers is six. The sum of the squares of the two numbers is twenty-six. Find the two numbers.

Your two numbers would be 5 and 1.