SOLUTION: A jar containing pennies, nickels and dimes is worth $8.40. The number of
dimes is six less than twice the number of pennies and there is an equal
number of dimes and nickels. Ho
Question 168521: A jar containing pennies, nickels and dimes is worth $8.40. The number of
dimes is six less than twice the number of pennies and there is an equal
number of dimes and nickels. How many nickels are in the jar. Found 2 solutions by Mathtut, josmiceli:Answer by Mathtut(3670) (Show Source):
You can put this solution on YOUR website! lets call the number of pennies p, nickels n, and dimes d.
.01p+.05n+.1d=8.4---eq 1
d=2p-6--------------eq 2
d=n-----------------eq 3
:
lets plug in values from eq 2 and 3 into eq 1 remembering that n=d
.01p+.05(2p-6)+.1(2p-6)=8.4
.01p+.1p-.3+.2p-.6=8.4
.31p=9.3
d=2(30)-6=54
and since d=n
then the number of nickels is 54
You can put this solution on YOUR website! Let = the number of pennies
Let = the number of nickels
Let = the number of dimes
Given:
(1) (in cents)
(2)
(3)
------------
From (2),
Substitute in (1)
Multiply both sides by
There are 54 nickels in the jar
Also,
Now check answer:
OK
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