SOLUTION: Using the point-slope form, how do you find the equation of a line that is perpendicular to the following equation: y = x/4 + 15. The perpendicular passes through points (-3,7)

Algebra ->  Linear-equations -> SOLUTION: Using the point-slope form, how do you find the equation of a line that is perpendicular to the following equation: y = x/4 + 15. The perpendicular passes through points (-3,7)      Log On


   

Question 168484: Using the point-slope form, how do you find the equation of a line that is perpendicular to the following equation: y = x/4 + 15. The perpendicular passes through points (-3,7)
Found 2 solutions by MRperkins, jojo14344:
Answer by MRperkins(300) About Me  (Show Source):
You can put this solution on YOUR website!
Given the point slope formula: y-y1=m(x–x1)
and the definition of perpendicular lines: The slopes of two perpendicular lines are opposite inverses. (example: 1/2 and -2/1; -3/2 and 2/3...)
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So we know that the slope of the new line is -4.
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y-7=-4%28x-%28-3%29%29
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y-7=-4%28x%2B3%29
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y-7=-4x-12
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y=-4x-5
.
I hope this helps!
.
Private tutoring is available. Click on my name to go to my website or email me at justin.sheppard.tech@hotmail.com for more information. If you have any other questions you can direct them to me personally and I will answer them for you.

Answer by jojo14344(1513) About Me  (Show Source):