SOLUTION: Factor completely 30z^8 + 44z^5 + 16z^2

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Question 168481This question is from textbook Introductory Algebra
: Factor completely
30z^8 + 44z^5 + 16z^2 This question is from textbook Introductory Algebra

Answer by MRperkins(300) About Me  (Show Source):
You can put this solution on YOUR website!
You can factor out 2z^2 from each term and you are left with 2z%5E2%2815z%5E6%2B22z%5E3%2B8%29
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*If you have trouble finding out if anything else will factor you can write out a factor tree for each term. %283%2Az%2Az%2Az%2Az%2Az%2Az%29%2B%282%2A11%2Az%2Az%2Az%29%2B%282%2A2%2A2%29
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Because there are no common terms to all of the terms then there is nothing left to factor.
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I hope this helps!
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Private tutoring is available. Click on my name to go to my website or email me at justin.sheppard.tech@hotmail.com for more information. If you have any other questions you can direct them to me personally and I will answer them for you.