SOLUTION: the width of a rectangle is 3ft less than the length. The perimerter is 62ft. Find the length and the width of the rectangle.

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: the width of a rectangle is 3ft less than the length. The perimerter is 62ft. Find the length and the width of the rectangle.      Log On


   

Question 168436This question is from textbook beginning and intermeidate alegebra 4th edition
: the width of a rectangle is 3ft less than the length. The perimerter is 62ft. Find the length and the width of the rectangle. This question is from textbook beginning and intermeidate alegebra 4th edition

Answer by midwood_trail(310) About Me  (Show Source):
You can put this solution on YOUR website!
The width of a rectangle is 3ft less than the length. The perimerter is 62ft. Find the length and the width of the rectangle.
width = x - 3
length = x
Perimeter = 62
62 = 2x + 2(x - 3)
62 = 2x + 2x - 6
62 = 4x - 6
62 + 6 = 4x
68 = 4x
68/4 = x
17 = x
The length is 17 feet.
The width is 3 less than 17 or 14 feet.