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Question 168390: Find four consecutive even integers such that four times the fourth decreased by one half the second is 9.
Found 3 solutions by checkley77, stanbon, Mathtut:
Answer by checkley77(12844)   (Show Source):
You can put this solution on YOUR website! LET X, X+2, X+4 & X+6 BE THE FOUR INTEGERS.
4(X+6)-(X+2)/2=9
4X+24-(X+2)/2=9
4X-(X+2)/2=9-24
(2*4X-X-2)/2=-15
8X-X-2=-30
7X=-30+2
7X=-28
X=-28/7
X=-4 ANS FOR THE SMALLEST INTEGER.
-4=2=-2 FOR THE NEXT INTEGER.
-4=4=0 FOR THE THIRD INTEGER.
-4+6=2 FOR THE LARGEST INTEGER.
PROOF:
4*2-(-2/2)=9
8-(-1)=9
8+1=9
9=9
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Find four consecutive even integers such that four times the fourth decreased by one half the second is 9.
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1st: 2x -2
2nd: 2x
3rd: 2x+2
4th: 2x+4
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EQUATION:
4(2x+4)-(1/2)(2x) = 9
8x+16 -x = 9
7x = -7
x = -1
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1st: -4
2nd: -2
3rd: 4
4th: 6
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Cheers,
Stan H.
Answer by Mathtut(3670) (Show Source):
You can put this solution on YOUR website! lets call our even integers.....x,x+2,x+4,x+6
4(x+6)-1/2(x+2)=9
4x+24-1/2x-1=9--->mult by 2
8x+48-x-2=18
7x=-28
integers are -4,-2,0,2
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