SOLUTION: the length of a certain rectangle is 4 cm longer than its width. if the width were increased by 6cm and the length were doubled, the new perimter would be twice the perimter of th

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: the length of a certain rectangle is 4 cm longer than its width. if the width were increased by 6cm and the length were doubled, the new perimter would be twice the perimter of th      Log On


   

Question 168365: the length of a certain rectangle is 4 cm longer than its width. if the width were increased by 6cm and the length were doubled, the new perimter would be twice the perimter of the original rectangle. find the dimensions of the orginal rectangle.
please send me the formula so i can figure it out
thank you
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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he length of a certain rectangle is 4 cm longer than its width. if the width were increased by 6cm and the length were doubled, the new perimter would be twice the perimter of the original rectangle. find the dimensions of the orginal rectangle.
;
Let x = the width of the original rectangle
Then
(x+4) = the length of the original rectangle
and
(x+6) = width of new rectangle
and
2(x+4) = length of new rectangle
:
New perimeter = twice old perimeter
2(2(x+4) + 2(x+6) = 2(2(x+4) + 2x)
4x + 16 + 2x + 12 = 4x + 16 + 4x
6x + 28 = 8x + 16