SOLUTION: How would you find the coordinates of the vertex for the following quadratic function?
{{{y=7x^2+6x-5}}}
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-> SOLUTION: How would you find the coordinates of the vertex for the following quadratic function?
{{{y=7x^2+6x-5}}}
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You can put this solution on YOUR website! y = 7x^2 + 6x -5
In this equation, a = 7, b = 6 and c = -5
We need to find the point (h,k), which is our vertex.
First we find h using: h = -b/2a
h = -6/2(7)
h = -6/14
h = -3/7
We now need to find k.
Plug -3/7 into the function given and simplify.
y = 7(-3/7)^2 + 6(-3/7) - 5
y = 7(9/49) - (18/7) - 5
y = (9/7) - (18/7) - 5
y = -9/7 - 5/1
y = -21/7
y = -3
The vertex is (-3/7, - 3)
Sorry for the wrong answer yesterday.
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