SOLUTION: Good afternoon, I need some help with this problem please. I been stuck on it for a week now. My text book is of no help, not enough examples. Thank you for your time. VR {1/x^

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Good afternoon, I need some help with this problem please. I been stuck on it for a week now. My text book is of no help, not enough examples. Thank you for your time. VR {1/x^      Log On


   



Question 168326This question is from textbook
: Good afternoon, I need some help with this problem please. I been stuck on it for a week now. My text book is of no help, not enough examples. Thank you for your time.
VR
{1/x^2-36}-{x+3/x^2-7x+6}
"1/x^2-36 is a fraction as is x+3/x^2-7x+6 I am to subract and then simplify if possible. It is asking for page number of my text this is in. This is a question the teacher gave me that is not in the text.
Thank you
This question is from textbook

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
{1/x^2-36}-{x+3/x^2-7x+6}
= [1/(x-6)(x+6)] - [(x+3)/(x-3)(x-2)]
lcd = (x-6)(x+6)(x-3)(x-2)
Rewrite each fraction with lcd as its denominator:
= [(x-3)(x-2]/lcd - [(x+3)(x+6)(x-6)]/lcd
Combine the numerators over the lcd:
= [x^2-5x+6-(x+3)(x^2-36)]/lcd
= [x^2-5x+6-x^3-36x+3x^2-108]/lcd
= [-x^3+4x^2-41x-102]/lcd
================================
Cheers,
Stan H.