SOLUTION: i need help with the following problems :22+4y-14=0 :4(x+5)=16 :-40-(-2x+5)=-61
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Question 16819
:
i need help with the following problems
:22+4y-14=0
:4(x+5)=16
:-40-(-2x+5)=-61
Answer by
LWahboo(3)
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22 + 4Y - 14 = 0
8 + 4Y = 0
4Y = - 8
Next divide by 4, the coefficient of Y.
Y = - 2
Check solutions by substituting each one in the original equation.
CHECKING SOLUTION #1: Y = -2
22 + 4Y - 14 = 0
4(-2) + 22 - 14 = 0
- 8 + 22 - 14 = 0
14 - 14 = 0
0 = 0
Solution: Y = -2
___________________________________________________
4 (X+5) = 16
Divide each side of equation by 4
(X+5) = 4
X + 5 = 4
Move constant 5 to the right.
X = - 5 + 4
Combine constants.
X = - 1
___________________________________________
- 40 - (-2X+5) = - 61
- 40 + 2X - 5 = - 61
Combine constants.
- 45 + 2X = - 61
Sort terms in decreasing powers.
2X - 45 = - 61
2X - 45 + 61 = 0
Combine constants.
2X + 16 = 0
Move constant 16 to the right.
2X = - 16
Next divide by 2, the coefficient of X.
X = - 8
Check solutions by substituting each one in the original equation.
CHECKING SOLUTION #1: X = -8
- 40 - (-2X+5) = - 61
- 40 - 21 = - 61
- 61 = - 61
Solution
Solution: X = -8