SOLUTION: Two traveler were 125 Kilometers apart at 2:00pm and were headed toward each other. If they met at 3:15p.m. and one was traveling 20 kilometers per hour faster than the other, wha

Algebra ->  Human-and-algebraic-language -> SOLUTION: Two traveler were 125 Kilometers apart at 2:00pm and were headed toward each other. If they met at 3:15p.m. and one was traveling 20 kilometers per hour faster than the other, wha      Log On


   

Question 168139: Two traveler were 125 Kilometers apart at 2:00pm and were headed toward each other. If they met at 3:15p.m. and one was traveling 20 kilometers per hour faster than the other, what was the speed of each traveler?
Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
lets call one travelers rate r and the other r+20. time is the same and lets call the distances x and 125-x
r(5/4)=x.........eq 1
(r+20)(5/4)=125-x..eq 2
lets use x's value from 1st equation and plug it into the 2nd eq
r+20(5/4)=125-(5/4)r
multiply both sides by 4
5r+100=500-5r
10r=400
highlight%28r=40%29speed of the slower traveler
highlight%28r%2B20=60%29speed of the faster traveler