Question 167913: A spice mixture is 25% thyme. How many grams of thyme must be added to 12 g of the mixture to increase the thyme content to 40%? Found 2 solutions by checkley77, ankor@dixie-net.com:Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! SORRY I MISREAD THE PROBLEM.
3 IS THE ANSWER.
.25*12+x=.40(12+x)
3+x=4.8+.4x
x-.4x=4.8-3
.6x=1.8
x=1.8/.6
x=3 g of tyme is used.
pROOF:
.25*12+3=.4(12+3)
3+3=.4*15
6=6
You can put this solution on YOUR website! A spice mixture is 25% thyme. How many grams of thyme must be added to 12 g
of the mixture to increase the thyme content to 40%?
:
Let 1x = amt of 100% thyme to be added
:
.25(12) + 1x = .40(x + 12)
:
3 + 1x = .4x + 4.8
:
1x - .4x = 4.8 - 3
:
.6x = 1.8
x =
x = 3 grams of Thyme to be added
:
:
Check solution in Thyme amt equation
.25(12) + 3 = .4(15)
3 + 3 = 6
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