SOLUTION: I am working with my school website on My Math Lab and this is a question asked. I need to solve for x.
4x(x-2)-5x(x-1)=2
I have already taken the steps to make the problem
4x^
Algebra ->
Rational-functions
-> SOLUTION: I am working with my school website on My Math Lab and this is a question asked. I need to solve for x.
4x(x-2)-5x(x-1)=2
I have already taken the steps to make the problem
4x^
Log On
Question 167899: I am working with my school website on My Math Lab and this is a question asked. I need to solve for x.
4x(x-2)-5x(x-1)=2
I have already taken the steps to make the problem
4x^2-8x-5x^2-5x=2, but that is all I have. I have been trying by "substitution", but have not found the answer. Please help me solve for x.
Thank you,
Rachel Found 2 solutions by checkley77, Earlsdon:Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! 4x(x-2)-5x(x-1)=2
4X^2-8X-5X^2+5X-2=0
-X^2-3X-2=0
X^2+3X+2=0
(X+2)(X+1)=0
X+2=0
X=-2 ANS.
X+1=0
X=-1 ANS.
PROOFS:
4*-2(-2-2)-5*-2(-2-1)=2
-8*-4+10*-3=2
32-30=2
2=2
4*-1(-1-2)-5*-1(-1-1)=2
-4*-3+5*-2=2
12-10=2
2=2
You can put this solution on YOUR website! Congratulation for trying, Rachel!
Solve for x: First, apply the distributive to both sets of parentheses. Now combine like-terms. Subtract 2 from both sides of the equation. Multiply through by -1 to make the terms positive and a little easier to work with. This will not change the result any. Now factor the trinomial. Apply the zero product rule: If A*B = 0, then either A = 0 or B = 0 or both, so... or which means that... or
You can verify the solution by substituting the values into original equation.
(