SOLUTION: Hello, the following question is from a past exam paper on algebra & complex numbers that I am looking at in order to revise for my Calculus exam. I have the answer in front of me
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Question 167773: Hello, the following question is from a past exam paper on algebra & complex numbers that I am looking at in order to revise for my Calculus exam. I have the answer in front of me, but I do not quite understand the working behind it, so if you could clear that up for me I would be grateful.
QUESTION SIX
Solve the following equation for x in terms of q: 2^(3x-1)=7^(x-q)
The assessment schedule says that the answer should be: x=(ln2-qln7)/(3ln2-ln7) or equivalent Found 2 solutions by jim_thompson5910, rviksub:Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website! 2^(3x-1)=7^(x-q)
Use the property ln a^b=b ln a
Take ln on both sides,
ln 2^(3x-1)=ln 7^(x-q)
(3x-1)ln2=(x-q)ln7
3xln2-ln2=xln7-qln7
3x ln2-x ln7=ln2 -q ln7
» x(3ln2-ln7)=ln2-qln7
» x= (ln2-qln7)/(3ln2-ln7)