Question 167752This question is from textbook Algebra 1
: Hello! My question says: The largest of the pyramids of Egypt has a square base with sides 755 feet long. Angles PQR has a mesure of 52 degrees. The top of the pyramid is no longer there. What was the pyramid's oringinal height RP to the nearest foot?
This question is from textbook Algebra 1
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! The largest of the pyramids of Egypt has a square base with sides 755 feet long. Angles PQR has a measure of 52 degrees. The top of the pyramid is no longer there. What was the pyramid's oringinal height RP to the nearest foot?
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The diagonal of the pyramid = 755sqrt(2)
Assuming PQR is an angle at one of the corners of the pyramid, you have
a right triangle with base = (755sqrt(2))/2, a base angle of 52 degrees,
and height = RP.
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EQUATION:
tangent(52) = h/[755sqrt(2)/2]
h = [755sqrt(2)/2]*tangent(52)
h = 533.8656..* 1.2799...
h = 683.32 feet
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Cheers,
Stan H.
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