SOLUTION: Can someone please help me in solving this problem. Thanks. Use long division to reduce (6x^5 - 5x^4 - 6x^3 - 10x^2 + 21x - 9)/(2x - 3).

Algebra ->  Equations -> SOLUTION: Can someone please help me in solving this problem. Thanks. Use long division to reduce (6x^5 - 5x^4 - 6x^3 - 10x^2 + 21x - 9)/(2x - 3).      Log On


   

Question 16772: Can someone please help me in solving this problem.
Thanks.
Use long division to reduce (6x^5 - 5x^4 - 6x^3 - 10x^2 + 21x - 9)/(2x - 3).
Answer by xcentaur(357) About Me  (Show Source):
You can put this solution on YOUR website!
(6x^5 - 5x^4 - 6x^3 - 10x^2 + 21x - 9)/(2x - 3)
Straight out let me tell you I have never liked long division. And looking at that,I suddenly remembered why. But anyhow, heres how it goes:

2x - 3 | 6x^5 - 5x^4 - 6x^3 - 10x^2 + 21x - 9 | 3x^4 + 2x^2 - 5x + 3
       | 6x^5 - 9x^4
               -     +
        ---------------
                       4x^4 - 6x^3
                       4x^4 - 6x^3
                      -     +
                      ------------
                                    -10x^2 + 21x
                                    -10x^2 + 15x
                                    +      -
                                   ------------
                                             6x - 9
                                             6x - 9
                                            -   +
                                           ----------
                                             [remainder = 0]


As you can see,the quotient is (3x^4+2x^3-5x+3) and there is no remainder. Hope this helps.
- Prabhat