SOLUTION: solve for b: {{{t = 9^square root of b}}}

Algebra ->  Square-cubic-other-roots -> SOLUTION: solve for b: {{{t = 9^square root of b}}}      Log On


   

Question 167693: solve for b:
t+=+9%5Esquare+root+of+b
Found 2 solutions by nerdybill, stanbon:
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
t+=+9%5Esqrt%28b%29
Take log9 (log base 9) of both sides:
log9%28t%29+=+sqrt%28b%29
Square both sides:
%28log9%28t%29%29%5E2+=+b+
log9%28t%29log9%28t%29+=+b+
2log9%28t%29+=+b+

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
solve for b:
t = 9^square root of b
------------
Take the log of both sides to get:
log(t) = (sqrt(b))log(9)
sqrt(b) = [log(t)/[log(9)]
b = [log(t)/[log(9)]^2
======================
A. b+=+t%5E2%2F81
B. b+=+t%2F81
C. b+=+t%2F9
D. none of the above
======================
The answer is "none of the above" for the problem you have posted.
If the answer is not "none of the above" the problem is not the
one you posted.
=======================================
Cheers,
Stan H.