Question 167644: The period of a pendulum is the amount of time it takes for the pendulum to complete one swing, returning to its original position. A pendulum's period varies directly as the square root of the pendulum's length and inversely as the square root of the acceleration due to gravity. Assuming the acceleration due to gravity is 980 cm/s^2, we find that the period is 6π seconds when the length is 289cm. What is the pendulum's period when its length is 121cm? ---> I was thinking P = period, L = length, A = acceleration, so the formula would be  , but everything just isn't quite coming out right to me. Help, please!
Found 3 solutions by stanbon, gonzo, Mathtut:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! The period of a pendulum is the amount of time it takes for the pendulum to complete one swing, returning to its original position.
A pendulum's period varies directly as the square root of the pendulum's length and inversely as the square root of the acceleration due to gravity.
P = k*sqrt(L)/a^2
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Assuming the acceleration due to gravity is 980 cm/s^2, we find that the period is 6π seconds when the length is 289cm.
Find "k":
6(pi) = k*sqrt(289)/980^2
6(pi) = k*17/960400
k = 1064889.03
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EQUATIOn for this pendulum:
P = 1064889.03*sqrt(289)/a^2
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What is the pendulum's period when its length is 121cm?
P = 1064889.03*sqrt(121)/980^2
P = 12.1968 seconds
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Cheers,
Stan H
Answer by gonzo(654) (Show Source):
Answer by Mathtut(3670) (Show Source):
You can put this solution on YOUR website! Hey Stanbon, hope all is well. I noticed that this problem read inversely as the the square root of the acceleration not the square ...you may want to revise your answer...mathtut
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