SOLUTION: My problem is: -(4w^-3z^-5)(8w)^2 I have the answer as (-4w^3z^5)(64w^-8) But I'm pretty sure that is wrong. Can you walk me through it? Thanks so much.

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: My problem is: -(4w^-3z^-5)(8w)^2 I have the answer as (-4w^3z^5)(64w^-8) But I'm pretty sure that is wrong. Can you walk me through it? Thanks so much.       Log On


   

Question 167495This question is from textbook Practice Workbook
: My problem is:
-(4w^-3z^-5)(8w)^2
I have the answer as
(-4w^3z^5)(64w^-8)
But I'm pretty sure that is wrong.
Can you walk me through it?
Thanks so much.
This question is from textbook Practice Workbook

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Simplify:
-%284w%5E%28-3%29%2Az%5E%28-5%29%29%288w%29%5E2 Square the last factor %288W%29%5E2+=+64w%5E2
-%284w%5E%28-3%29%2Az%5E%28-5%29%29%2864w%5E2%29 Multiply the integers.4%2A64+=+256
-%28256w%5E%28-3%29%2Az%5E%28-5%29%29%28w%5E2%29 Multiply the w's by adding their exponents. w%5E%28-3%29%2Aw%5E2+=+w%5E%28-1%29
-%28256w%5E%28-1%29%2Az%5E%28-5%29%29 Simplify by putting the factors with negative exponents into the denominator thus making the exponents positive.
-%28256%2F%28w%2Az%5E5%29%29 or you can write this as: %28-256%29%2F%28wz%5E5%29