SOLUTION: A single die is tossed thirteen times. Find the probability that exactly eleven of the tosses show a "three."
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Question 167425: A single die is tossed thirteen times. Find the probability that exactly eleven of the tosses show a "three." Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A single die is tossed thirteen times. Find the probability that exactly eleven of the tosses show a "three."
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P(x=11) = 13C11* (1/2)^11 * (1/2)^2 = [13*12/1*2](1/2)^13 = 78/8192 = 0.0095..
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Cheers,
Stan H.
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