SOLUTION: If Train A & Train B are traveling the same direction on parallel tracks. Train A is going 60 MPH, Train B is going 80 MPH. Train A passes a station at 12:20 PM. If Train B pass

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Question 167421: If Train A & Train B are traveling the same direction on parallel tracks. Train A is going 60 MPH, Train B is going 80 MPH. Train A passes a station at 12:20 PM. If Train B passes the same station at 12:32 PM, what time will Train B catch up to Train A?
Found 2 solutions by checkley77, ptaylor:
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
60t=80(t-.2)
60t=80t-16
60t-80t=-16
-20t=-16
t=-16/-20
t=.8 hours or 48 minutes after 12:30 or @ 1:18 pm. they will meet.

Answer by ptaylor(2198) About Me  (Show Source):
You can put this solution on YOUR website!

Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r
We are basically told that Train B is 12 min behind Train A.
Let t=amount of time needed for Train B to catch up with Train A after Train B passes the station
Distance train A has travelled from the station when Train B catches up=60*(12/60)+60t
Distance train B has travelled from the station when it catches Train A=80t
When the above two distances are equal, train B will have caught Train A, so:
60*(12/60)+60t=80t
12+60t=80t subtract 60 t from each side
12=80t-60t
20t=12 divide each side by 20
t=12/20=6/10=3/5 hr=36 min----time needed for Train B to catch Train A
Therefore, Train B catches Train A at 12:32 + 36 min=1:08 PM
CK
12+60(3/5)=80(3/5)
12+36=3*16
48=48


Hope this helps---ptaylor