SOLUTION: Slove the equation. ln(x^(2)-5)=ln(2x)+ln(x-3)

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Slove the equation. ln(x^(2)-5)=ln(2x)+ln(x-3)      Log On


   

Question 167362: Slove the equation.
ln(x^(2)-5)=ln(2x)+ln(x-3)
Answer by oscargut(2103) About Me  (Show Source):
You can put this solution on YOUR website!
ln%28x%5E%282%29-5%29=ln%282x%29%2Bln%28x-3%29
then
ln%28x%5E%282%29-5%29=ln%282x%28x-3%29%29
then
x%5E2-5=2x%5E2-6x
then
x%5E2-6x%2B5=0
then
x+=+%286+%2B-+sqrt%28+16+%29%29%2F%282%29+=
x+=+%286+%2B-+4%29%2F%282%29+
then x=5 or x=1
but if x=1 then ln%28x%5E2-5%29=ln%28-4%29 ( does not exists)
so
Answer is : x=5